mergesort: remove llist_mergesort()

Now that all of its callers are gone, remove llist_mergesort().

Signed-off-by: René Scharfe <l.s.r@web.de>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
René Scharfe 2022-07-16 19:02:38 +02:00 committed by Junio C Hamano
parent 9b9f5f6217
commit 0f1eb7d6e9
3 changed files with 0 additions and 90 deletions

View File

@ -973,7 +973,6 @@ LIB_OBJS += merge-ort.o
LIB_OBJS += merge-ort-wrappers.o
LIB_OBJS += merge-recursive.o
LIB_OBJS += merge.o
LIB_OBJS += mergesort.o
LIB_OBJS += midx.o
LIB_OBJS += name-hash.o
LIB_OBJS += negotiator/default.o

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@ -1,76 +0,0 @@
#include "cache.h"
#include "mergesort.h"
/* Combine two sorted lists. Take from `list` on equality. */
static void *llist_merge(void *list, void *other,
void *(*get_next_fn)(const void *),
void (*set_next_fn)(void *, void *),
int (*compare_fn)(const void *, const void *))
{
void *result = list, *tail;
int prefer_list = compare_fn(list, other) <= 0;
if (!prefer_list) {
result = other;
SWAP(list, other);
}
for (;;) {
do {
tail = list;
list = get_next_fn(list);
if (!list) {
set_next_fn(tail, other);
return result;
}
} while (compare_fn(list, other) < prefer_list);
set_next_fn(tail, other);
prefer_list ^= 1;
SWAP(list, other);
}
}
/*
* Perform an iterative mergesort using an array of sublists.
*
* n is the number of items.
* ranks[i] is undefined if n & 2^i == 0, and assumed empty.
* ranks[i] contains a sublist of length 2^i otherwise.
*
* The number of bits in a void pointer limits the number of objects
* that can be created, and thus the number of array elements necessary
* to be able to sort any valid list.
*
* Adding an item to this array is like incrementing a binary number;
* positional values for set bits correspond to sublist lengths.
*/
void *llist_mergesort(void *list,
void *(*get_next_fn)(const void *),
void (*set_next_fn)(void *, void *),
int (*compare_fn)(const void *, const void *))
{
void *ranks[bitsizeof(void *)];
size_t n = 0;
if (!list)
return NULL;
for (;;) {
int i;
size_t m;
void *next = get_next_fn(list);
if (next)
set_next_fn(list, NULL);
for (i = 0, m = n;; i++, m >>= 1) {
if (m & 1)
list = llist_merge(ranks[i], list, get_next_fn,
set_next_fn, compare_fn);
else if (next)
break;
else if (!m)
return list;
}
n++;
ranks[i] = list;
list = next;
}
}

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@ -1,19 +1,6 @@
#ifndef MERGESORT_H
#define MERGESORT_H
/*
* Sort linked list in place.
* - get_next_fn() returns the next element given an element of a linked list.
* - set_next_fn() takes two elements A and B, and makes B the "next" element
* of A on the list.
* - compare_fn() takes two elements A and B, and returns negative, 0, positive
* as the same sign as "subtracting" B from A.
*/
void *llist_mergesort(void *list,
void *(*get_next_fn)(const void *),
void (*set_next_fn)(void *, void *),
int (*compare_fn)(const void *, const void *));
/* Combine two sorted lists. Take from `list` on equality. */
#define DEFINE_LIST_MERGE_INTERNAL(name, type) \
static type *name##__merge(type *list, type *other, \